A ball is dropped from $405$ meters and rebounds two-thirds the distance it falls each time it bounces. How many meters will the ball have traveled when it hits the ground the fourth time?

Question

Reiny · Accepted Answer

Don't know how you got that answer, but ... 405 + 540+360+240 = 1545

Reiny · Answer

distance covered in bounce #1 -- 405 metres
distance covered in bounce #2 --- 2(2/3)(405) = 540 m, 270 each way
distance covered in bounce #3 = 2(2/3)(270) = 360 m , 180 each way
distance covered in bounce #4 = 2(2/3)(180) = 240 m

add them up

Brendan Zankowski · Answer

Im sorry, but check your work, when I input the answer, 1095, it says wrong