The terminal velocity of an object falling through a fluid can be calculated using the following equation:
Vt = √((2 * m * g)/(ρ * A * Cd))
Where:
Vt = terminal velocity
m = mass of the object
g = acceleration due to gravity (approximately 9.8 m/s²)
ρ = density of the fluid (air in this case)
A = surface area of the object
Cd = coefficient of drag
Plugging in the given values:
Vt = √((2 * 0.15 * 9.8)/(1.225 * 0.0026 * 0.007))
Calculating:
Vt ≈ 30.4 m/s
So the ball's terminal velocity is approximately 30.4 m/s.
A ball falls from a tall bridge. The ball has a mass of 0.15 kg. The air density is 1.225 kg/m3 . The ball’s surface area is 0.0026 m2 . The ball’s coefficient of drag is 0.007. What is the ball’s terminal velocity?(1 point) Responses 164 m/s 164 m/s 30.4 m/s 30.4 m/s 363 m/s 363 m/s 402 m/s
1 answer