a. V^2 = Vo^2 + 2g*h
Vo = 0
g = 9.8 m/s^2
h = 50 m.
Solve for V.
a ball dropped from rest at a height of 50 m above the ground. (a) what is the speed just before it hits the ground? (b) how long does it take to reach the ground?
5 answers
50
(0)^2_2*9.8*50
a. -31
b . 3.16 sec
b . 3.16 sec
490