B. Conservation is conserved in both directions.
In the path of the origianl ball:
m*44+m*0=m*.707v1+m*cos30 v2
in the perpenduclar path
0=m*.707v1+m*sin30*V2
two equations, two unknowns. solve for v1 and v2
Now add up the final KEnergies, do they equal the original KE?
A ball A having a speed of 44.0 ms-1
collides with another ball, B, of the same mass
which is initially at rest. After the collision A is deflected, 45.0 from its initial direction and
B moves off at an angle of 30.0° to the original direction of A.
a. What is the nature of the collision? (1 Mark)
b. What is the speed of each ball after the collision?
1 answer