To find the probability that the baker made enough cookies (no more than 70 sold), we need to calculate the z-score first.
z-score = (X - μ) / σ
where:
X = number of cookies sold (70)
μ = mean number of cookies sold (92)
σ = standard deviation (9)
z-score = (70 - 92) / 9
z-score = -22 / 9
z-score ≈ -2.44
Next, we look up the z-score in a standard normal distribution table or use a calculator to find the probability.
The probability of selling no more than 70 cookies is equal to the probability of having a z-score less than or equal to -2.44.
Using a standard normal distribution table or calculator, we find that the probability of z ≤ -2.44 is approximately 0.0073.
Therefore, the probability that the baker made enough cookies (no more than 70 sold) is approximately 0.0073, rounded to the nearest tenth.
A bakery owner wants to ensure they make enough cookies each day to meet the demand from customersOn average, they sell 92 cookies a day with a standard deviation of 9. The baker makes 70 cookies each day Using a calculator or a spreadsheet programfind the probability that the baker made enough cookies (no more than 70 cookies sold that day)Round the answer to the nearest tenth
1 answer