the average velocity during the 2m is 2/.22sec. That average velocity occurs at the center, or 1 m off the ground.
Now, at the top, Vi=0
V(1m)=Vi+gt
solve for t, time to fall all but the last meter.
hf=ho+Vi*t-4.9t^2
1=ho-4.9t^2 solve for ho using the time above.
A bag of sand dropped by a would-be assassin from the roof of a building just misses Tough Tony, a gangster 2-m tall. The missile traverses the height of Tough Tony in 0.22 s, landing with a thud at his feet. How high was the building? Ignore friction.
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