First calculate the total numebr of candies:
12+11+5+6+5+16=55
(check my work, because my calculator sometimes misses a digit).
There are 11 yellow candies out of the 55.
If you pick (not choose) without looking one after another, this is what is called pick without replacement.
If two yellow candies are required, the probability to pick the first one is therefore 11/55.
Since there are now 10 left out of 54 (without replacement), the probability of picking a yellow this time is 10/54.
The probability that both events will occur is therefore the product of the two, namely
11/55*10/54.
I will leave you to calculate the final answer. Don't forget to cancel common factors if you present it in fraction form (my preference).
A bag of M&Ms contains 12 red, 11 yellow, 5 green, 6 orange, 5 blue, and 16 brown candies. What is the probability that if you choose 2 M&Ms from the bag (one after the other) without looking, you will choose 2 yellow ones?
1 answer