A bag contains tiles with the letters P-R-O-B-A-B-I-L-I-T-Y. Tyler chooses a tile without looking and doesn’t replace it. He chooses a second tile without looking. What is the probability that he will choose the letter I both times?

Question

A. one over fifty-five
B. two over fifty-five
C. two over one hundred twenty-one
D. three over one hundred twenty-one.

Answer 1

There are 11 tiles in the bag. The probability of choosing an I on the first draw is 2/11, since there are two I's in the bag. After one I has been chosen and not replaced, there is only one I left out of 10 tiles, so the probability of choosing an I on the second draw is 1/10. Therefore, the probability of choosing I both times is:

(2/11) * (1/10) = 2/110 = 1/55

So the answer is (A) one over fifty-five.