The probability of drawing a red marble is 8/17 and the probability of drawing a blue marble is 5/17.
P(red and blue) = P(red) * P(blue) = (8/17) * (5/17) = 40/289
Therefore, the probability of drawing a red and blue marble from the bag is 40/289.
A bag contains 8 red marbles, 4 white marbles, and 5 blue marbles. You draw one marble at random. Find P(red and blue).
3 answers
its 0
Apologies for the mistake. You are correct.
Since a marble cannot be both red and blue at the same time, the probability of drawing a marble that is both red and blue is indeed 0. Thank you for pointing that out.
Since a marble cannot be both red and blue at the same time, the probability of drawing a marble that is both red and blue is indeed 0. Thank you for pointing that out.