A bag contains 7 green marbels 9 red marbels 10 orange marbels 5 brown marbels and 10 blue marbels you choose a marble replace it and choose again what is p(red, then blue)?

Answer 1

The probability of choosing a red marble on the first pick is 9/41 (since there are 9 red marbles out of 41 total marbles). After replacing the marble, the probability of choosing a blue marble on the second pick is 10/41 (since there are 10 blue marbles out of 41 total marbles).

Therefore, the probability of selecting a red marble then a blue marble is:

P(red, then blue) = P(red) x P(blue | red)
P(red, then blue) = (9/41) x (10/41)
P(red, then blue) = 90/1681 or approximately 0.0535

So the probability of selecting a red marble then a blue marble is approximately 0.0535.