A bag contains 6 blue marbles, 7 green marbles, and 9 yellow marbles. Twice you draw a marble and replace it. Find P(yellow, then green). c:
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2 answers
There are 9+7+6=22 marbles in total. The probability of selecting a yellow marble would be 9/22. By replacing that yellow marble with a green marble, you aren't changing the total marble count, so the probability of selecting a green marble would be 7/22. Because the two events are independent, their probabilities will get multiplied. Therefore, P(Yellow, then Green) = P(Yellow) * P(Green) = 9/22 * 7/22 = 63/484.
A bag contains 8 blue marbles, 6 green marbles, 12 yellow marbles, and 10 orange marbles. A marble is drawn at random from the bag.
What is the probability that the marble drawn will not be blue? its 2/9
What is the probability that the marble drawn will not be blue? its 2/9
17 answers