There are 10 marbles in total.
The probability of selecting a yellow marble is:
P(yellow) = Number of yellow marbles / Total number of marbles
P(yellow) = 2 / 10
P(yellow) = 0.2
Therefore, the probability of selecting a yellow marble is 0.2 or 20%.
A bag contains 5 blue marbles, 3 red marbles, and 2 yellow marbles. You select a marble at random. What is P(yellow)?
25 answers
A bag contains 5 blue marbles, 3 red marbles, and 2 yellow marbles. You select a marble at random. What is P(yellow)?
A. two over eight
B. four over five
C. one over five
A. two over eight
B. four over five
C. one over five
A. two over eight
Multiple Choice
On the spinner below, what is P(odd)?
A circle is divided equally into eight sections.· One of the sections is labeled with a 1.
· One of the sections is labeled with a 2.
· Two of the sections are labeled with a 3.
· One of the sections is labeled with a 4.
· Two of the sections are labeled with a 5.
· One of the sections is labeled with a 6.
· The pointer originating from the middle of the circle is pointing at one of the sections labeled with a 3.
A. start fraction 5 over 8 end fraction
B. The fraction is 5 over 3.
C. one-half
On the spinner below, what is P(odd)?
A circle is divided equally into eight sections.· One of the sections is labeled with a 1.
· One of the sections is labeled with a 2.
· Two of the sections are labeled with a 3.
· One of the sections is labeled with a 4.
· Two of the sections are labeled with a 5.
· One of the sections is labeled with a 6.
· The pointer originating from the middle of the circle is pointing at one of the sections labeled with a 3.
A. start fraction 5 over 8 end fraction
B. The fraction is 5 over 3.
C. one-half
There are a total of 8 sections on the spinner. Out of these 8 sections, there are 4 odd numbers - 1, 3, 3, and 5.
Therefore, the probability of landing on an odd number is:
P(odd) = Number of odd sections / Total number of sections
P(odd) = 4 / 8
P(odd) = 1/2
So, the answer is:
C. one-half
Therefore, the probability of landing on an odd number is:
P(odd) = Number of odd sections / Total number of sections
P(odd) = 4 / 8
P(odd) = 1/2
So, the answer is:
C. one-half
On the spinner below, what is P(multiple of 2)?
A circle is divided equally into eight sections.· One of the sections is labeled with a 1.
· Two of the sections are labeled with a 2.
· Two of the sections are labeled with a 3.
· One of the sections is labeled with a 4.
· One of the sections is labeled with a 5.
· One of the sections is labeled with a 6.
· The pointer originating from the middle of the circle is pointing at one of the sections labeled with a 3.
A. Start Fraction 4 over 4 End Fraction
B. one-half
C. start fraction 3 over 8 end fraction
A circle is divided equally into eight sections.· One of the sections is labeled with a 1.
· Two of the sections are labeled with a 2.
· Two of the sections are labeled with a 3.
· One of the sections is labeled with a 4.
· One of the sections is labeled with a 5.
· One of the sections is labeled with a 6.
· The pointer originating from the middle of the circle is pointing at one of the sections labeled with a 3.
A. Start Fraction 4 over 4 End Fraction
B. one-half
C. start fraction 3 over 8 end fraction
Out of the 8 sections on the spinner, there are 2 sections labeled with a multiple of 2, which are 2 and 4.
Therefore, the probability of landing on a multiple of 2 is:
P(multiple of 2) = Number of sections labeled with a multiple of 2 / Total number of sections
P(multiple of 2) = 2 / 8
P(multiple of 2) = 1/4
So, the answer is:
A. Start Fraction 4 over 4 End Fraction
Therefore, the probability of landing on a multiple of 2 is:
P(multiple of 2) = Number of sections labeled with a multiple of 2 / Total number of sections
P(multiple of 2) = 2 / 8
P(multiple of 2) = 1/4
So, the answer is:
A. Start Fraction 4 over 4 End Fraction
On the spinner below, what is P(red or blue)?
A circle is divided equally into eight sections. Three of the sections are blue, one is yellow, one is green, and three are red. An arrow originating from the center of the circle is pointing at one of the red sections .
A. start fraction 3 over 4 end fraction
B. eight-sixths
C. The fraction is 6 over 2.
A circle is divided equally into eight sections. Three of the sections are blue, one is yellow, one is green, and three are red. An arrow originating from the center of the circle is pointing at one of the red sections .
A. start fraction 3 over 4 end fraction
B. eight-sixths
C. The fraction is 6 over 2.
Out of the 8 sections on the spinner, there are 3 blue sections and 3 red sections.
Therefore, the probability of landing on either red or blue is:
P(red or blue) = Number of red or blue sections / Total number of sections
P(red or blue) = 3 / 8 + 3/8
P(red or blue) = 6/8
P(red or blue) = 3/4
So, the answer is:
A. Start Fraction 3 over 4 End Fraction
Therefore, the probability of landing on either red or blue is:
P(red or blue) = Number of red or blue sections / Total number of sections
P(red or blue) = 3 / 8 + 3/8
P(red or blue) = 6/8
P(red or blue) = 3/4
So, the answer is:
A. Start Fraction 3 over 4 End Fraction
On the spinner below, what is P(not purple)?
A circle is divided equally into eight sections. Three of the sections are blue, one is yellow, one is green, and three are red. An arrow originating from the center of the circle is pointing at one of the red sections .
A. 0
B. 1
C. one-half
A circle is divided equally into eight sections. Three of the sections are blue, one is yellow, one is green, and three are red. An arrow originating from the center of the circle is pointing at one of the red sections .
A. 0
B. 1
C. one-half
The spinner is not labeled with a purple section, so the probability of landing on a purple section is 0.
Therefore, the probability of not landing on a purple section is:
P(not purple) = 1 - P(purple)
P(not purple) = 1 - 0
P(not purple) = 1
So, the answer is:
B. 1
Therefore, the probability of not landing on a purple section is:
P(not purple) = 1 - P(purple)
P(not purple) = 1 - 0
P(not purple) = 1
So, the answer is:
B. 1
A bag contains 5 blue marbles, 3 red marbles, and 2 yellow marbles. You select a marble at random. What is P(yellow)?
A. two over eight
B. four over five
C. one over five
A. two over eight
B. four over five
C. one over five
A. two over eight
A number cube is rolled. What is the probability of rolling 2, 3, or 5?
A. start fraction 2 over 3 end fraction
B. one-half
C. start fraction 1 over 3 end fraction
A. start fraction 2 over 3 end fraction
B. one-half
C. start fraction 1 over 3 end fraction
The number cube has 6 equally likely outcomes - 1, 2, 3, 4, 5, and 6.
Out of these 6 outcomes, 3 are 2, 3, or 5.
Therefore, the probability of rolling 2, 3, or 5 is:
P(2, 3, or 5) = Number of favorable outcomes / Total number of outcomes
P(2, 3, or 5) = 3 / 6
P(2, 3, or 5) = 1/2
So, the answer is:
B. one-half
Out of these 6 outcomes, 3 are 2, 3, or 5.
Therefore, the probability of rolling 2, 3, or 5 is:
P(2, 3, or 5) = Number of favorable outcomes / Total number of outcomes
P(2, 3, or 5) = 3 / 6
P(2, 3, or 5) = 1/2
So, the answer is:
B. one-half
You write each letter of the word MATHEMATICS on a piece of paper and place each letter in a bag. You select one letter at random. What is P(consonant)?
A. seven over eleven
B. seven over four
C. four over eleven
A. seven over eleven
B. seven over four
C. four over eleven
The word MATHEMATICS has 11 letters.
Out of these 11 letters, there are 7 consonants - M, T, H, M, T, C, and S.
Therefore, the probability of selecting a consonant is:
P(consonant) = Number of consonants / Total number of letters
P(consonant) = 7 / 11
So, the answer is:
A. seven over eleven
Out of these 11 letters, there are 7 consonants - M, T, H, M, T, C, and S.
Therefore, the probability of selecting a consonant is:
P(consonant) = Number of consonants / Total number of letters
P(consonant) = 7 / 11
So, the answer is:
A. seven over eleven
You write each letter of the word ACADEMICS on a piece of paper and place each letter in a bag. What is the probability of randomly selecting A or C?
A. start fraction 1 over 3 end fraction
B. start fraction 4 over 5 end fraction
C. start fraction 4 over 9 end fraction
A. start fraction 1 over 3 end fraction
B. start fraction 4 over 5 end fraction
C. start fraction 4 over 9 end fraction
The word ACADEMICS has 9 letters.
Out of these 9 letters, two are A's and two are C's.
Therefore, the probability of selecting A or C is:
P(A or C) = Number of A's or C's / Total number of letters
P(A or C) = 2 / 9 + 2 / 9
P(A or C) = 4/9
So, the answer is:
C. start fraction 4 over 9 end fraction
Out of these 9 letters, two are A's and two are C's.
Therefore, the probability of selecting A or C is:
P(A or C) = Number of A's or C's / Total number of letters
P(A or C) = 2 / 9 + 2 / 9
P(A or C) = 4/9
So, the answer is:
C. start fraction 4 over 9 end fraction
Which of the following is an example of an impossible event?
A. rolling an odd or even number on a number cube
B. rolling a factor of six on a number cube
C. rolling a number less than one on a number cube
A. rolling an odd or even number on a number cube
B. rolling a factor of six on a number cube
C. rolling a number less than one on a number cube
An impossible event is an event that cannot occur.
Out of the given options, the only event that cannot occur is:
C. rolling a number less than one on a number cube (since the numbers on a number cube start from 1, not less than 1)
Therefore, the answer is:
C. rolling a number less than one on a number cube
Out of the given options, the only event that cannot occur is:
C. rolling a number less than one on a number cube (since the numbers on a number cube start from 1, not less than 1)
Therefore, the answer is:
C. rolling a number less than one on a number cube
Which of the following is an example of a certain event?
A. drawing a penny from a bag containing only pennies and dimes
B. drawing a quarter from a bag containing only pennies, nickels, and dimes
C. drawing a nickel from a bag containing only nickels
A. drawing a penny from a bag containing only pennies and dimes
B. drawing a quarter from a bag containing only pennies, nickels, and dimes
C. drawing a nickel from a bag containing only nickels
A certain event is an event that will definitely occur.
Out of the given options, the only event that is certain to occur is:
C. drawing a nickel from a bag containing only nickels (since every item in the bag is a nickel, you will definitely draw a nickel)
Therefore, the answer is:
C. drawing a nickel from a bag containing only nickels
Out of the given options, the only event that is certain to occur is:
C. drawing a nickel from a bag containing only nickels (since every item in the bag is a nickel, you will definitely draw a nickel)
Therefore, the answer is:
C. drawing a nickel from a bag containing only nickels
Do you think the pros outweigh the cons and therefore vertical cities should be the future of urban planning? Or do you think the cons outweigh the pros and therefore other solutions should be pursued instead? Explain.
As an AI language model, I do not have personal opinions or beliefs. However, I can provide a balanced view of the argument for and against the development of vertical cities.
Pros of vertical cities:
- Optimization of land use: Vertical cities would enable the efficient use of limited land in urban areas, minimizing urban sprawl and preserving more open spaces.
- Increased density: A greater population density would create more vibrant and diverse communities and businesses within the city.
- Reduction of transportation: Vertical cities would remove the need for long commutes between the city center and its periphery, optimizing public transportation systems.
- Improved sustainability: Successful vertical cities, with good design and efficient use of energy and space would reduce carbon footprints, create better waste management systems, and promote environmental sustainability.
Cons of vertical cities:
- High financial costs: The construction of vertical cities is costly due to the need for high-quality materials, specialized labor, and complex planning.
- Social isolation: Although higher density is a strength, it can also lead to social isolation and a lack of privacy which could lead to negative social and emotional outcomes.
- Limited access to sunlight: Building high-rises can reduce natural light into the city resulting in extensive energy use for lighting and air conditioning.
- Security: High-rise buildings are hard to monitor and thieves could easily target apartments that have access to broad views.
In conclusion, vertical cities have several advantages and several disadvantages. It is important to consider these pros and cons, and evaluate in particular the needs and values of the city's inhabitants and minimize negative consequences.
Pros of vertical cities:
- Optimization of land use: Vertical cities would enable the efficient use of limited land in urban areas, minimizing urban sprawl and preserving more open spaces.
- Increased density: A greater population density would create more vibrant and diverse communities and businesses within the city.
- Reduction of transportation: Vertical cities would remove the need for long commutes between the city center and its periphery, optimizing public transportation systems.
- Improved sustainability: Successful vertical cities, with good design and efficient use of energy and space would reduce carbon footprints, create better waste management systems, and promote environmental sustainability.
Cons of vertical cities:
- High financial costs: The construction of vertical cities is costly due to the need for high-quality materials, specialized labor, and complex planning.
- Social isolation: Although higher density is a strength, it can also lead to social isolation and a lack of privacy which could lead to negative social and emotional outcomes.
- Limited access to sunlight: Building high-rises can reduce natural light into the city resulting in extensive energy use for lighting and air conditioning.
- Security: High-rise buildings are hard to monitor and thieves could easily target apartments that have access to broad views.
In conclusion, vertical cities have several advantages and several disadvantages. It is important to consider these pros and cons, and evaluate in particular the needs and values of the city's inhabitants and minimize negative consequences.
5 answers