First, we need to find the probability of choosing a blue marble on the first draw, which is 3/12 (since there are 12 marbles total and 3 of them are blue). Then, on the second draw, we have 11 marbles left, since we did not replace the first one. There are now only 5 red marbles left out of the 11, so the probability of choosing a red marble on the second draw is 5/11.
To find the probability of both events happening together (choosing a blue marble, then a red marble), we multiply the probabilities:
3/12 * 5/11 = 15/132
Simplifying this fraction, we get:
5/44
Therefore, the answer is A. five over forty-four.
A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing a blue marble, then a red marble if the marbles are not replaced.
A. five over forty-four
B. fifteen over thirty-five
C. two-thirds
D. one over fifteen .
1 answer