A bag contains 4 white, 3 blue, and 5 red marbles.
1. Probability of choosing a red marble, then a white marble with replacement = probability of choosing a red marble * probability of choosing a white marble = (5/12)*(4/12) = 5/36. Answer: B. five over thirty-six
2. Probability of choosing 3 blue marbles in a row with replacement = probability of choosing a blue marble * probability of choosing another blue marble * probability of choosing another blue marble = (3/12)*(3/12)*(3/12) = 1/64. Answer: D. one over sixty-four
3. Probability of choosing a blue marble, then a red marble without replacement = probability of choosing a blue marble * probability of choosing a red marble from remaining marbles = (3/12)*(5/11) = 15/132 = 5/44. Answer: A. five over forty-four
4. Probability of choosing 2 white marbles in a row without replacement = probability of choosing a white marble * probability of choosing another white marble from remaining marbles = (4/12)*(3/11) = 1/11. Answer: A. the fraction states 1 over 11.
A bag contains 4 white, 3 blue, and 5 red marbles.
1. Find the probability of choosing a red marble, then a white marble if the marbles are replaced. (1 point)
one-twelfth
five over thirty-six
five-sixths
five-twelfths
A bag contains 4 white, 3 blue, and 5 red marbles.
2. Find the probability of choosing 3 blue marbles in a row if the marbles are replaced. (1 point)
two over eleven
one over two hundred twenty
Fraction 1 over 27 end fraction
one over sixty-four
A bag contains 4 white, 3 blue, and 5 red marbles.
3. Find the probability of choosing a blue marble, then a red marble if the marbles are not replaced. (1 point)
five over forty-four
fifteen over thirty-five
two-thirds
one over fifteen
A bag contains 4 white, 3 blue, and 5 red marbles.
4. Find the probability of choosing 2 white marbles in a row if the marbles are not replaced. (1 point)
The fraction states 1 over 11.
one-ninth
two-thirds
Start Fraction 1 over 16 End Fraction
3 answers
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