a bag contains 3 blue marbles 9 green marbles and 11 yellow marbles twice you draw a marble and replace it. find P(blue, then green)

1 answer

The probability of drawing a blue marble and then a green marble is equal to the product of the probability of drawing a blue marble on the first draw (which is 3/23, since there are 3 blue marbles out of 23 total marbles) and the probability of drawing a green marble on the second draw (which is also 9/23, since we replaced the first marble).

Therefore, P(blue, then green) = (3/23) x (9/23) = 27/529.

The answer is 27/529.