A bag contains 3 blue 5 red 4 green and 2 white balls. Find the chance of drawing at random one ball without replacement which is not white

1 answer

To find the probability of drawing a ball that is not white from the bag, we first need to determine the total number of balls and the number of non-white balls.

Step 1: Count the total number of balls

  • Blue balls: 3
  • Red balls: 5
  • Green balls: 4
  • White balls: 2

Total number of balls: \[ 3 + 5 + 4 + 2 = 14 \]

Step 2: Calculate the number of non-white balls

The non-white balls are blue, red, and green:

  • Blue: 3
  • Red: 5
  • Green: 4

Total non-white balls: \[ 3 + 5 + 4 = 12 \]

Step 3: Calculate the probability of drawing a non-white ball

The probability \( P \) of an event is given by the formula: \[ P(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]

In this case, the favorable outcomes are drawing a non-white ball, and the total outcomes are drawing any ball.

Thus, the probability of drawing a non-white ball is: \[ P(\text{not white}) = \frac{\text{Number of non-white balls}}{\text{Total number of balls}} = \frac{12}{14} \]

Step 4: Simplify the fraction

\[ P(\text{not white}) = \frac{12}{14} = \frac{6}{7} \]

Therefore, the chance of drawing one ball that is not white is \(\frac{6}{7}\).