If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
A. 7/9 * 2/(9-1) = ?
B. 2/9 * (2-1)/9-1) = ?
C. Use similar processes for this question.
A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn.
A) What is the probability of selecting a purple marble and then a white marble? B) What is the probability of selecting two white marbles? C) Is there a greater chance of selecting two white marbles in a row or two purple marbles in a row? Show your work.
PLZ HURRY UP URGENT I HAVE TO SUBMIT BY 8:30
22 answers
I agree
a.
\frac{7purple}{9total} * \frac{2white}{8total} \\ \frac{14}{72} \\ =0.194
The denominator of the second number goes down one because you aren't replacing the initial marble pulled, making the amount of marbles in the bag go down, but not affecting the white count because you pulled a purple marble.
b.
\frac{2white}{9total} * \frac{1white}{8total} \\ \frac{2}{72} \\ =0.278
The same can be said about the denominator for this problem, but not the numerator. The numerator must go down one number as well, because you already chose one white marble, taking one of the white marbles out of the bag, leaving you with one solitary, white marble.
c.
Chance of selecting two purple marbles:
\frac{7purple}{9total} * \frac{6purple}{8total} \\ \frac{42}{72} \\ =0.583
Chance of selecting two white marbles:
\frac{2white}{9total} * \frac{1white}{8total} \\ \frac{2}{72} \\ =0.278
Chance of selecting two purple vs. Chance of Selecting 2 white:
0.583>0.278.
It is more likely to select 2 purple marbles.
Hope this helps
\frac{7purple}{9total} * \frac{2white}{8total} \\ \frac{14}{72} \\ =0.194
The denominator of the second number goes down one because you aren't replacing the initial marble pulled, making the amount of marbles in the bag go down, but not affecting the white count because you pulled a purple marble.
b.
\frac{2white}{9total} * \frac{1white}{8total} \\ \frac{2}{72} \\ =0.278
The same can be said about the denominator for this problem, but not the numerator. The numerator must go down one number as well, because you already chose one white marble, taking one of the white marbles out of the bag, leaving you with one solitary, white marble.
c.
Chance of selecting two purple marbles:
\frac{7purple}{9total} * \frac{6purple}{8total} \\ \frac{42}{72} \\ =0.583
Chance of selecting two white marbles:
\frac{2white}{9total} * \frac{1white}{8total} \\ \frac{2}{72} \\ =0.278
Chance of selecting two purple vs. Chance of Selecting 2 white:
0.583>0.278.
It is more likely to select 2 purple marbles.
Hope this helps
First off it is cheating but this website is made for that purpose they either give you the math problem as well for you to find out or they just give the answers and either way at least the kid is getting 100 and not a 0 for this so calm down.
@me! Thank you for explaining about how to get the answer it really helped a lot I've been stuck on the question for about an hour now trying to figure out the probability of a purple marble, then a white marble being selected.
I appreciate this very much. This will help my daughter a lot. Also, everyone stop arguing. If your parents saw the way your acting and speaking, what would they say. If my daughter saw this and did this I would trace my steps and see she got this from here. High five to y'all's foreheads!!!!
ANSWER THE DANG QUESTION US KIDS ARE TRYING TO PASS OUR GRADE OK
please just answer the question
please just answer the question
in general, the probability of some event
= number of times that event can happen/total number of possible outcomes
so ...
you have 2 white and 7 purple
prob of purple = 7/9
then
prob of white = 2/8 , there are only 8 left since you drew one already.
prob(purple, then white) = (7/9)(2/4) = 7/36
prob(2 whites) = (2/9)(1/8) = 1/36
prob(2 purples) = 7/9(6/8) = 7/12
and of course 7/12 > 1/36
clearly , since you had more purples than whites, the chances of getting purples would be greater than the chances of getting whites.
prob of getting the 5 on the spin = 1/6
prob of getting a pair = 6/36 =1/6
So she has the same chance of winning at either games, makes no difference.
= number of times that event can happen/total number of possible outcomes
so ...
you have 2 white and 7 purple
prob of purple = 7/9
then
prob of white = 2/8 , there are only 8 left since you drew one already.
prob(purple, then white) = (7/9)(2/4) = 7/36
prob(2 whites) = (2/9)(1/8) = 1/36
prob(2 purples) = 7/9(6/8) = 7/12
and of course 7/12 > 1/36
clearly , since you had more purples than whites, the chances of getting purples would be greater than the chances of getting whites.
prob of getting the 5 on the spin = 1/6
prob of getting a pair = 6/36 =1/6
So she has the same chance of winning at either games, makes no difference.
Why r u trying to stop us from cheating it is not working
The person who originally asked this question is a sophomore now lol
none of you are getting the answer unless if someone gives it to you
I'm going to miss this when I go back to school next year...
THOU SHALL NOT CHEAT...
Thou Shalt haveth no other Gods before Me
Read the Bible idiot that's not a comandment
Read the Bible idiot that's not a comandment
so which one is it?
thank you for your help people
@God Stop trying to stop us from CHECKING our answers, granted some of us are cheating, THAT'S OUR CHOICE! So leave us alone Mr. "I aM gOd" ;-;
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