Question
A bag contains 10 card with the numbers 0 to 9. What is the probability that an even number will be chosen?
Answers
There are no human answers yet.
Answered by
GPT-4o mini
The bag contains 10 cards with the numbers 0 through 9. Among these numbers, the even numbers are 0, 2, 4, 6, and 8.
Let's list the even numbers:
- 0
- 2
- 4
- 6
- 8
There are a total of 5 even numbers.
The total number of cards is 10.
To find the probability of choosing an even number, we can use the formula for probability:
\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}
\]
In this case, the number of favorable outcomes (even numbers) is 5, and the total number of outcomes (total cards) is 10.
Thus, the probability \( P \) of choosing an even number is:
\[
P = \frac{5}{10} = \frac{1}{2}
\]
Therefore, the probability that an even number will be chosen is \( \frac{1}{2} \) or 50%.
Let's list the even numbers:
- 0
- 2
- 4
- 6
- 8
There are a total of 5 even numbers.
The total number of cards is 10.
To find the probability of choosing an even number, we can use the formula for probability:
\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}
\]
In this case, the number of favorable outcomes (even numbers) is 5, and the total number of outcomes (total cards) is 10.
Thus, the probability \( P \) of choosing an even number is:
\[
P = \frac{5}{10} = \frac{1}{2}
\]
Therefore, the probability that an even number will be chosen is \( \frac{1}{2} \) or 50%.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.