A bacterial population starts at 500 and doubles every four days. Find a formula for the population after t days and find the percentage rate of change in population.

Answer 1

population= Original*(2^(t/5))

rate of change
dpopulation/dt= t/5 * ln2* 2^(t/5) * original

for percentate, then percent= 100*dpopulation/dt / original= 100*t/5*ln2*2^t/5