A bacterial population in a broth culcture has been growing exponentially. It was at a density of 4300 individuals per mL two hours ago and is now 5850 individuals per mL. What was the density 4 hours and 15 minutes ago?

Answer 1

5850 = 4300 e^(8r) ... ln(5850/4300) = 8 r

5850 = d e^(17r)

Answer 2

Let me amplify:
5850 = 4300 e^(rate*time) and time is 2 hrs
1/2 ln(5850/4300)=rate
rate=.154
Now, 4 .25 hrs ago
5850 =N e^.154*4.25 taking ln of each side
ln5850=ln(N) + .6545
ln N=8.674-6545
N=e^8.0105
N=3012

Answer 3

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