using the usual conventions, let's say
ABC is a triangle with A=38°, C=72° and b=5.82cm.
I still have no idea what "line abc" is supposed to be, since a,b,c are sides of the triangle.
But, you know that A+B+C = 180°, so B = 70°
Now, using the law of sines,
a/sinA = c/sinC = b/sinB = 5.82/sin70°
A b c is a triangle with a 38 degree,c 72degree and b 5.82cm find line abc
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