xA = - 8 , yA = - 4
xB = - 2 , yB = 6
xC = 4 , yC = - 4
AB = √ ( ( xA - xB)² + ( yA - yB )² )
AB = √ ( ( - 8 - ( - 2) )² + ( - 4 - 6 )² )
AB = √ ( ( - 8 + 2)² + ( - 10 )² )
AB = √ ( ( - 6 )² + 100 )
AB = √ ( 36 + 100 )
AB = √ 136
AB = √ ( 4 ∙ 34 )
AB = √4 ∙ √34
AB = 2 √34
BC = √ ( ( xB - xC)² + ( yB - yC )² )
BC = √ ( ( - 2 - 4 )² + ( 6 - ( - 4 )² )
BC = √ ( ( - 6 )² + ( 6 + 4 )² )
BC = √ ( 36 + 10² )
BC = √ ( 36 + 100 )
BC= √ 136
BC = √ ( 4 ∙ 34 )
BC = √4 ∙ √34
BC = 2 √34
AC = √ ( ( xA - xC)² + ( yA - yC )² )
AC = √ ( ( - 8 - 4)² + ( - 4 - (- 4 ) )² )
AC = √ ( ( - 12 )² + ( - 4 + 4 )² )
AC = √ ( 144 + 0² )
AC = √ 144
AC = √12
Your triangle has two sides of equal length AB = 2 √34 and BC = 2 √34
So your triangle is isosceles triangle.
Perimeter:
P = AB + BC + AC
P = 2 √34 + 2 √34 + √12
P = 4 √34 + 12
P = 4 √34 + 4 ∙ 3
P = 4 ( √34 + 3 )
A,B & C are the points (-8, -4), (-2, 6) and (4, -4) respectively. show that ABC is an isosceles triangle. find the perimeter of the triangle
1 answer