Did you make your sketch.
After I filled in the angles I found angle A to be 90°
so you have a right-angled triangle.
Yeahhh, Pythagoras!
I can find the other angles!
tanB = 800/280 = ...
angle B = appr 70.7°
then angle C = 90-70.7 = 19.3°
state the result as a "bearing"
A, B and C are three towns, the bearing of B and C from A being 295° and 205°, and their distances from A are 280km and 800km respectively. Find the bearing of C from B to the nearest minute.
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