A and B are twos 360 km apart. An express bus departs from A at 8 a.m. and maintains an average speed of 90 km/h between A and B. Another bus starts From B also at 8.m. and moves towards A making four stops at four equally spaced points between B and A. Each stop is of duration 5 minutes and the average speed between any two spots is 60 km/h. Calculate distance distance the two buses at 10 a.m.
2 answers
In 2 hours without stopping,bus A travels 90*2=180km since bus B stopped for a total of 20 minutes,it is clear it only travelled for 2-1/3=1hour 40mins distance it travelled =5/3*60=100km distance at ten a.m=360-180-100=80km
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