A. A uniform, upward-pointing electric field E of magnitude 3.00~103 N/C has been set up between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have length L = 4 cm and separation d = 2.00 cm. An electron is then shot between the plates from the left edge of the lower plate. The initial velocity v0 of the electron makes an angle ƒÆ=45‹ with the lower plate and has a magnitude of 6.93~106 m/s. Will the electron strike one of the plates? If so, what is the horizontal distance from the left edge? If not enter the vertical position at which the particle leaves the space between the plates ( m).

Question

A. A uniform, upward-pointing electric field E of magnitude 3.00~103 N/C has been set up between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have length L = 4 cm and separation d = 2.00 cm. An electron is then shot between the plates from the left edge of the lower plate. The initial velocity v0 of the electron makes an angle ƒÆ=45‹ with the lower plate and has a magnitude of 6.93~106 m/s. Will the electron strike one of the plates? If so, what is the horizontal distance from the left edge? If not enter the vertical position at which the particle leaves the space between the plates ( m).

B.The next electron has an initial velocity which has the same angle ƒÆ=45‹ with the lower plate and has a magnitude of 5.83~106 m/s. Will this electron strike one of the plates? If so, what is the horizontal distance from the left edge? If not enter the vertical position at which the particle leaves the space between the plates ( m).

drwls · Answer

Can you express your angles some other way that ƒÆ=45‹ ? I can't make sense of that

Andy · Answer

sorry its theta=45 degrees for both questions