Let Vi be the initial velocity and Vf be the final velocity at the top of the ramp.
Use the conservation of total mechanical energy equation for both your problems. The mass M cancels out.
(M/2)Vi^2 = (M/2)Vf^2 + M g H
This can be rewritten
Vf^2 = Vi^2 - 2 g H
H is the ramp height in meters
g = 9.8 m/s^2
(a) a person in a wheelchair approaches a 0.50-m-high ramp with a speed of 3.5 m/sec. calculate the final speed of the wheelchair at the top of the ramp if the person coasts up and friction is negligible.
(b) what initial speed would be necessary to be 1.0 m.sec?
i need this asap :( thank you!!!!
1 answer
1 answer