A) A hot air balloon has just lifted off and is rising at the constant rate of 1.70 m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 10.4 m/s. If the passenger is 3.00 m above her friend when the camera is tossed, how much time does it take for the camera to reach her?

B)How high is the passenger when the camera reaches her?

1 answer

camera:
Vi = 10.4

v = Vi - g t

h = 10.4 t - 4.9 t^2

passenger:
v = 1.7
h = 3 + 1.7 t

when are the two heights the same?

3 + 1.7 t = 10.4 t - 4.9 t^2
solve quadratic for t

then use h = 3 + 1.7 t to get height