90*9.81 * sin 34
90*9.81 * cos 34
A)A 90 kg crate is pushed at constant speed up the frictionless 34° ramp shown in the figure. What horizontal force F is required?
B)What force is exerted by the ramp on the crate?
4 answers
Part A keeps be marked wrong. Is my answer supposed to be 493.7 N ?
oops. I did not see force had to be horizontal
F up slope = F cos 30
F cos 34 = 90 * 9.81 * sin 34
F = 90*9.81 * tan 34
F = 596 N
F up slope = F cos 30
F cos 34 = 90 * 9.81 * sin 34
F = 90*9.81 * tan 34
F = 596 N
then on crate force of weight increased by F sin 34
90*9.81* cos 24 + 596 sin 34
= 1065 N
90*9.81* cos 24 + 596 sin 34
= 1065 N