a 95-kg person stands on a scale in an elevator. What is the apparent weight when the elevator is:

Question

(A) accelerating upward with an acceleration of 1.8 m/s^2 (answer 1.1 * 10^3 N)
(B) moving upward at a constant speed (answer 931 N)
(C) accelerating downward with an acceleration of 1.3 m/s^2 (answer 7.68 m/s)

Answer 1

F = force up from scale

F - m g = m a
F = m(9.81+a)

A) F = 95(9.81+1.8) = 1.103*10^3 N

B) a = 0 so F = 95*9.81 = 932 N I get. Perhaps you are using 9.8 instead of 9.81 for g

C) F = 95(9.8 - 1.3) = 807 N
I do not know how you got strange answer

Answer 2

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