A 920 g empty iron kettle is put on a stove. How much heat in joules must it absorb to raise its temperature from 15.0° C to 93.0° C? (The specific heat for iron is 113 cal/kg · °C.)(1 cal = 4.184 J)

Answer 1

q=Mass*specific heat*change in temp=(0.920kg)(113cal/kg *C)(78 C). Take answer for that you get and multiply it by 4.184J/cal.