9*g - T = 9*a
T - 5*g*0.2 = 5*a
8*g = 14 a
a = 5/7 g
T = 9 g - 9 a = 9 g - 45/7 g
= 18/7 g Newtons
A 9 kg hanging weight is connected by a string over a pulley to a 5 kg block sliding on a flat
table. If the coefficient of sliding friction is 0.2, find the tension in the string.
1 answer
1 answer