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a=9

b=40
c=?
A2+B2=C2
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Given that a = 9 and b = 40, let's find the value of c using the Pythagorean theorem:

a^2 + b^2 = c^2

9^2 + 40^2 = c^2

81 + 1600 = c^2

1681 = c^2

Taking the square root of both sides, we get:

c = √1681

c ≈ 41

Therefore, the value of c is approximately 41.
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