A 873-kg (1930-lb) dragster, starting from rest completes a 403.7-m (0.2523-mile) run in 4.920 s. If the car had a constant acceleration, what would be its acceleration and final velocity?

Answer 1

http://www.jiskha.com/display.cgi?id=1290754007

Answer 2

V = d / t = 403.7 / 492 = 82.1 m/s.

a = (Vf - Vo) / t,
a = (82.1 - 0) / 4.92 = 16,7 m/s^2.