Initial momentum = (Friction force) x Time
Solve for the time
The friction force is
m * g * Uk = 850*9.8*0.2 = 1666 N
Be sure to convert 32.5 km/hr to m/s when computing the momentum.
A 850 kg car skidding on an icy highway at
32.5 km/h slides onto some bare pavement. If the
coefficient of friction between the tires and the bare
pavement is 0.200, what time(s) does it take for the
car to stop? HOW do i get the answer!!!!
3 answers
thats wtong tho, the answer is 4.60s i just don't know how to get that
My answer was NOT wrong. You just did not follow my directions in finishing it.
The speed is 9.03 m/s.
The momentum is m*v = 7674 kg m/s
The time is 7674/1666 = 4.60 s
It would be the same for any mass; m cancels out in the end.
The speed is 9.03 m/s.
The momentum is m*v = 7674 kg m/s
The time is 7674/1666 = 4.60 s
It would be the same for any mass; m cancels out in the end.
1 answer