A 85 kg man weighs 833 N on the Earth's surface. How far above the surface of the Earth would he have to go to "lose" 18% of his body weight?

Answer 1

gravitational force (weight) is inversely proportional to the square of the distance between the masses

Earth radius ... 6.38E6 m

[6.38E6 / (6.38E6 + h)^2 = 1 - .18 ... 6.38E6 = (h + 6.38E6) √.82

solve for h