work=INT force dx=INT (15750+9900x-27500x^2) dx integrate that, from x=0 to 0.582
b. Now use new upper limit 1.11
c. compare
A 85-g bullet is fired from a rifle having a barrel 0.582 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is 15750 + 9900x - 27500x2, where x is in meters.
(a) Determine the work done by the gas on the bullet as the bullet travels the length of the barrel.
kJ
(b) If the barrel is 1.11 m long, how much work is done?
kJ
(c) How does this value compare with the work calculated in part (a)?
percent difference = %
1 answer
1 answer