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A 85.2-mg sample of the compound X4O10 contains 48.0 mg of oxygen atoms. What is the atomic mass of element X?Asked by College
A 85.2-mg sample of the compound X4O10 contains 48.0 mg of oxygen atoms. What is the atomic mass of element X?
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Answered by
Damon
85.2 - 48 = 37.2 mg of X
4 X atoms for every 10 O atoms
10 * 16 = 160
4 * X = 4x
4x/160 = 37.2/48
4 X = 160 *37.2/48
X = 31
check
31 * 4 = 124
16 *10 =160
124/160 = .775
and
37.2/48 = .775 good
4 X atoms for every 10 O atoms
10 * 16 = 160
4 * X = 4x
4x/160 = 37.2/48
4 X = 160 *37.2/48
X = 31
check
31 * 4 = 124
16 *10 =160
124/160 = .775
and
37.2/48 = .775 good
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