A 8 V flashlight battery has an internal resistance of 1.7 Ω when new, and 8 Ω when old. Imagine this is a resistor in series with the battery mounted INSIDE the battery itself, which describes the chemical degradation of the battery with age. Calculate the voltage across a 14 Ω lamp (the load) when the battery is new. Express the answer with one decimal place.

asked by Naina

13 years ago

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1 answer

Rt = 1.7 + 14 = 15.7 Ohms.

I = E/Rt = 8/15.7 = 0.51A,

V = IRl = 0.51 * 14 = 7.1 Volts across
lamp.

answered by Henry

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Question

A 8 V flashlight battery has an internal resistance of 1.7 Ω when new, and 8 Ω when old. Imagine this is a resistor in series with the battery mounted INSIDE the battery itself, which describes the chemical degradation of the battery with age. Calculate the voltage across a 14 Ω lamp (the load) when the battery is new. Express the answer with one decimal place.

1 answer

Rt = 1.7 + 14 = 15.7 Ohms.

I = E/Rt = 8/15.7 = 0.51A,

V = IRl = 0.51 * 14 = 7.1 Volts across
lamp.

Ask a New Question or answer this question.

Henry · Answer

Rt = 1.7 + 14 = 15.7 Ohms. I = E/Rt = 8/15.7 = 0.51A, V = IRl = 0.51 * 14 = 7.1 Volts across lamp.