The normal force on the plane from weight is mgCosTheta. The component of force due to weight down the plane is mgSinTheta.
Work down the plane is Ffriction*distance, or mg*mu*SinTheta*distance.
Work done by gravity is mg*distancedownplane*SinTheta Think that out...
A 8 kg crate is placed at rest on an incline plane (s=0.8, k=0.5), whose angle is 60o. It then slides 3 m down the incline.
work done by gravity: ?J
work done by friction force: ?J
Using your results from part a, find the speed of the crate after sliding this distance.
1 answer
1 answer