Remember, acid + base = salt + water
Ba(OH)2 + 2HI ==> 2H2O + BaI2.
A 8.71 g sample of an aqueous solution of hydroiodic acid contains an unknown amount of the acid.
If 25.0 mL of 0.388 M barium hydroxide are required to neutralize the hydroiodic acid, what is the percent by weight of hydroiodic acid in the mixture?
I understand how to solve this. The only problem I am having is coming up with the balanced equation. Please help, thank you!!
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