M1*V1 + M2*V2[90o] = 2.59m/s[23.9o]
8.34*2.4 + 0.170*V2[90o] = 2.59[23.9o]
20.02 + 0.170*V2[90] = 2.37 + 1.05i
0.170V2[90] = 2.37-20.02 + 1.05i
0.170V2[90] = -19 + 1.05i
0.170V2{90] = 19.03[176.8o]
V2 = 112m/s[86.8o] = Velocity of the puck.
A 8.34kg lump of clay travels east on frictionless ice at a speed of 2.40 m/s. A .170 kg hockey puck travels northward and collides with the clay. After the collision, both objects stick together, and move off at a speed of 2.59 m/s in a direction of 23.9* north of east. What was the hockey pucks speed before the collision.
1 answer
1 answer