g carbon = 8.13-0.301-4.22 = ??g
% C = (??g/8.13)*100
3.39 x (%C/100) = xx
A 8.13 g sample of HCN is found to contain 0.301 g of H and 4.22 g of N.
Find the mass of carbon in a sample of HCN with a mass of 3.39 g.
1 answer