A 8.0 kg object, moving with a constant velocity of 8.0 m/s, is acted upon by a force of 14 N in the direction of the motion for 6.0 s. What is the velocity (in meters/second) of the object at the end of this time?

Answer 1

The impulse applied by the force is 14*6 = 84 kg*m/s

The initial momentum of 64 kg*m/s will increase to 64 + 84 = 148 kg*m/s, and the new velocity will be 148/8 = 18.5 m/s