A 8.0×10−2 kg arrow hits the target at 25 m/s and penetrates 3.8 cm before stopping.

What average force did the target exert on the arrow?
What average force did the arrow exert on the target?

2 answers

Vf^2=Vi^2+2ad

Vf=0, Vi given, d given, solve for a.

Force=m*a
that formula gets me a wrong answer...