A 78 g basketball is launched at an angle of 45.4◦ and a distance of 10.1 m from the basketball goal. The ball is released at the same height (ten feet) as the basketball goal’s height.

Question

A 78 g basketball is launched at an angle of 45.4◦ and a distance of 10.1 m from the basketball goal. The ball is released at the same height (ten feet) as the basketball goal’s height.
A basketball player tries to make a long jump-shot as described above.
The acceleration of gravity is 9.8 m/s2 . What speed must the player give the ball?

Henry · Accepted Answer

Range = Vo^2*sin(2A)/g = 10.1 m. Vo^2*sin(90.8)/9.8 = 10.1 0.102Vo^2 = 10.1 Vo^2 = 98.99 Vo = 9.95 m/s.