%H = 0.290/78.9*100 = ?
%N = 4.06/78.9*100 = ?
%C = 100-%H-%N = ?
Then mass C in 3.37 g sample HCN = 3.37 x (%C/100) = ?
A 78.9g sample of HCN contains 0.290g of H and 4.06g of N. Find the mass of carbon in a sample of HCN with a mass of 3.37 g
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