mg=76300 N, m=76300/9.8 kg, s= 418 m,
v₀=66.5 mph =29.7 m/s
v=28.9 mph=12.2 m/s, h=10.7 m
KE1-KE2= W(dr)+ PE
m•v₀²/2 - m•v²/2= F(dr) •s +m•g•h
Solve for “F(dr)”
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A 76.3-kN car is travelling at 66.5 mph when the driver decides to exit the freeway by going up a ramp. After coasting 418 m along the exit ramp the car\'s speed is 27.3 mph, and it is h = 10.7 m above the freeway. What is the magnitude of the average drag force exerted on the car?
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