A .7567 impure KHP was dissolved in water. 26.7 ml of standardized 0.068 M NaOH was used to achieve a phenolphthalein end point. The stoichiometric ratio between KHP and NaOH is 1:1.

Question

A .7567 impure KHP was dissolved in water. 26.7 ml of standardized 0.068 M NaOH was used to achieve a phenolphthalein end point. The stoichiometric ratio between KHP and NaOH is 1:1.
What is the percent by mass of KHP in the sample?

DrBob222 · Answer

mols NaOH = M x L = estimated 0.0018 Therefore, mols KHP = estimated 0.0018 g KHP = mols KHP x molar mass KHP = ? % KHP = (mass KHP.mass sampe)*100 = ?