A 75 g arrow is fired horizontally. the bow string exerts an average force of 65 N on the arrow over a distance of 0.90 m. With what speed does the arrow leave the bow string?

Answer 1

a = F/m = 65/0.075 = 867 m/s^2.

V^2 = Vo^2 + 2a*d = 0 + 2*867*.9 = 1560
V = 39.5 m/s.