A 73 kg man in a 7.0 kg chair tilts back so that all the weight is balanced on two legs of the chair. Assume that each leg makes contact with the floor over a circular area with a radius of 1.0 cm, and find the pressure exerted on the floor by each leg.
3 answers
pressureEachLeg= weight/area * 1/2
so would it be...
P=((73+7)*9.8)/2*pi*r then divide it by 2?
or would it be...
4P=((73+7)*9.8)/2*pi*r then divide it by 2?
P=((73+7)*9.8)/2*pi*r then divide it by 2?
or would it be...
4P=((73+7)*9.8)/2*pi*r then divide it by 2?
No. Area of a circle is PI r^2
so the denominator is / PI r^2 *1/2
which changes all to
pressure= 2*80*g/PI(.01)^2
so the denominator is / PI r^2 *1/2
which changes all to
pressure= 2*80*g/PI(.01)^2